Quiz HOTS
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Materi : Eksponen
Diketahui persamaan [tex]2x^2 . 4^{-2x} = \frac{1}{8}[/tex] . Jika x1 < x 2 , maka x1 - x2
latex rusak = cek web
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Materi : Eksponen
Diketahui persamaan [tex]2x^2 . 4^{-2x} = \frac{1}{8}[/tex] . Jika x1 < x 2 , maka x1 - x2
latex rusak = cek web
Penjelasan :
[tex] {2}^{x {}^{2} } . \: {4}^{ - 2x} = \frac{1}{8} \\ {2}^{ {x}^{2} } . \: \: {2}^{ - 4x} = {2}^{ - 3} \\ {2}^{ {x}^{2} - 4x} = {2}^{ - 3} \\ {x}^{2} - 4x = - 3 \\ {x}^{2} - 4x + 3 = 0 \\ (x - 3)(x - 1) = 0 \\ x = 3 \: atau \: x = 1[/tex]
= x1 < x2
= 1 < 3
= 1 <3
= x1 - x2
= 1 - 3
= -2
[answer.2.content]